
(d) [image:14_image245.png]
The output $Y$ is
$Y = \overline{(A + B)} \bullet C$
The truth table of the given circuit is as shown in the table
[table] $A$ | $B$ | $C$ | $\overline{A + B}$ | $Y = \overline{(A + B)}.C$ ; 0 | 0 | 0 | 1 | 0 ; 0 | 0 | 1 | 1 | 1 ; 0 | 1 | 0 | 0 | 0 ; 0 | 1 | 1 | 0 | 0 ; 1 | 0 | 0 | 0 | 0 ; 1 | 0 | 1 | 0 | 0 ; 1 | 1 | 0 | 0 | 0 ; 1 | 1 | 1 | 0 | 0 [/table]