Q. In the circuit given $A,\ B$ and $C$ are inputs and $Y$ is the output

The output of $Y$ is

A) High for all the high inputs
B) High for all the low inputs
C) High when$\ A = 1,\ B = 1,\ C = 0$
D) Low for all low inputs
Explanation

(d) [image:14_image245.png]
The output $Y$ is
$Y = \overline{(A + B)} \bullet C$
The truth table of the given circuit is as shown in the table
[table] $A$ | $B$ | $C$ | $\overline{A + B}$ | $Y = \overline{(A + B)}.C$ ; 0 | 0 | 0 | 1 | 0 ; 0 | 0 | 1 | 1 | 1 ; 0 | 1 | 0 | 0 | 0 ; 0 | 1 | 1 | 0 | 0 ; 1 | 0 | 0 | 0 | 0 ; 1 | 0 | 1 | 0 | 0 ; 1 | 1 | 0 | 0 | 0 ; 1 | 1 | 1 | 0 | 0 [/table]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.