Q. The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is $1\ K\Omega$. The peak value for an A.C input voltage of 0.01 $V$ of collector current is
A) 100 $\mu A$
B) 0.01 $mA$
C) 0.05 $mA$
D) 500 $\mu A$
Explanation
(d) $\beta = 50,\ R_{i} = 1000\ \Omega,\ V_{i} = 0.01V$
$\beta = \frac{i_{c}}{i_{b}}$ and $i_{b} = \frac{V_{i}}{R_{i}} = \frac{0.01}{10^{3}} = 10^{- 5}A$
Hence $i_{c} = 50 \times 10^{- 5}A = 500\ \mu A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.