Q. If in a triode valve amplification factor is 20 and plate resistance is 10 k$\Omega$, then its mutual conductance is
A) 2 milli mho
B) 20 milli mho
C) ($\frac{1}{2}$) milli mho
D) 200 milli mho
Explanation
(a) Amplification factor $\mu$ = 20
Plate resistance $R_{p} =$10 k$\Omega$ = ${10 \times 10}^{3}\Omega$
$\therefore\ $Mutual conductance
$g_{m} = \frac{\mu}{R_{p}} = \frac{20}{{10 \times 10}^{3}} = {2 \times 10}^{- 3}$ mho
= 2 milli mho
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.