Q. When the forward bias voltage of a diode is changed from 0.6 V to 0.7 V, the current changes from 5 mA to 15 mA. Then its forward bias resistance is
A) 0.01 $\Omega$
B) 0.1$\ \Omega$
C) 10$\ \Omega$
D) 100$\ \Omega$
Explanation
(c) Forward biased resistance = $\frac{\mathrm{\Delta}V}{\mathrm{\Delta}I} = \frac{0.7 - 0.6}{(15 - 5) \times 10^{- 3}}$
$= \frac{0.1}{{10 \times 10}^{- 3}} = 10\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.