Q. In the following circuit the equivalent resistance between $A$ and $B$ is
A) $\frac{20}{3}\Omega$
B) 10 $\Omega$
C) 16 $\Omega$
D) 20 $\Omega$
Explanation
(c) According to the given figure $A$ is at lower potential $w.r.t.\ B$. hence both diodes are in reverse biasing, so equivalent circuit can be redrawn as follows
$\Rightarrow$ Equivalent resistance between $A$ and $B$
$R = 8 + 2 + 6 = 16\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.