If $\alpha\ and\ \beta\ $are the current gain in the$\ CB$ and $CE$ configurations respectively of the transistor circuit, then $\frac{\beta - \alpha}{\alpha\beta}$ is equal

Question

Dr. Abubacker · Accepted Answer

(b) The relation between$\ \alpha\ and\ \beta\ $is
$\beta = \frac{\alpha}{1 - \alpha}$
Putting this value in the given equation, we have
$\frac{\beta - \alpha}{\alpha\beta} = \frac{\frac{\alpha}{1 - \alpha} - \alpha}{\alpha \bullet \frac{\alpha}{1 - \alpha}} = \frac{\alpha^{2}}{\alpha^{2}} = 1$

Q. If $\alpha\ and\ \beta\ $are the current gain in the$\ CB$ and $CE$ configurations respectively of the transistor circuit, then $\frac{\beta - \alpha}{\alpha\beta}$ is equal

Explanation

Reviewed by Dr. Abubacker

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