Q. For a transistor the parameter $\beta = 99$. The value of the parameter is
A) 0.9
B) 0.99
C) 1
D) 9
Explanation
(b) $\alpha = \frac{\beta}{1 + \beta} = \frac{99}{1 + 99} = 0.99$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.