Q.
The current $I$ through 10 $\Omega$ resistor in the circuit given below is
A) 50 mA
B) 20 mA
C) 40 mA
D) 80 mA
Explanation
(d) Here, diode $D_{2}$ is reverse biased while $D_{1}$ is forward biased.
So, no current flows across $D_{2},\ current\ flows\ through\ diode\ D_{1}$.
$I = \frac{V}{R} = \frac{2}{10 + 15} = \frac{2}{15} = 0.08$ A = 80 mA.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.