(a) Here the emitter base junction of $N$-$P$-$N$ transistor is forward biased with battery $V_{BB}$ through resistance $R$. When the value of $R$ is reduced, then the emitter current $i_{e}$ will increase. As a result the collector current will also increase. ($i_{c} = i_{e} - i_{b}$). Due to increase in $i_{c}$, the potential difference across $L$ increases and hence the reading of voltmeter will increases