Q. In an $NPN$ transistor the collector current is $24\ mA$. If 80% of electrons reach collector its base current in $mA$ is

A) 36
B) 26
C) 16
D) 6
Explanation

(d) Given $i_{c} = \frac{80}{100} \times i_{e} \Rightarrow 24 = \frac{80}{100} \times i_{e} \Rightarrow i_{e} = 30\ mA$
By using $i_{e} = i_{b} + i_{c} \Rightarrow i_{b} = 30 - 24 = 6\ mA$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.