Q.
A p-n junction in series with a resistance of 5 k$\Omega$ is connected across a 50 V DC source. If the forward bias resistance of the junction is 50 $\Omega,\ the\ forward$ bias current is
A) 8.8 mA
B) 1 mA
C) 2 mA
D) 9.9 mA
Explanation
(d) Total resistance = 50 + 5000 = 5050 $\Omega$
$\therefore$ Forward current $i = \frac{50}{5050} = \frac{1}{101} = \ $9.9 mA
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.