Q. In a transistor if collector current is $25\ mA$ and base current is $1\ mA$, then current amplification factor $\alpha$ is
A) $\frac{25}{24}$
B) $\frac{24}{25}$
C) $\frac{25}{26}$
D) $\frac{26}{25}$
Explanation
(c) Here,
Collector current, $I_{C} = 25mA$
Base current, $I_{B} = 1mA$
As $I_{E} = I_{B} + I_{C} = (1 + 25)mA = 26mA$
As $\alpha = \frac{I_{C}}{I_{E}} = \frac{25mA}{26mA} = \frac{25}{26}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.