In a triode, $g_{m} = 2 imes 10^{- 3}\ ohm^{- 1};\ \mu = 42$, resistance load, $R = 50\ k\Omega$. The voltage amplification obtained from this triode will be

Question

In a triode, $g_{m} = 2 	imes 10^{- 3}\ ohm^{- 1};\ \mu = 42$, resistance load, $R = 50\ k\Omega$. The voltage amplification obtained from this triode will be

Dr. Abubacker · Accepted Answer

(b) $A_{v} = \frac{\mu R}{r_{p} + R} = \frac{\mu R}{(\mu/g_{m}) + R}$
$= \frac{42 	imes (50 	imes 10^{3})}{42/(2 	imes 10^{- 3}) + 50 	imes 10^{3}}$
$= 29.57$

Q. In a triode, $g_{m} = 2 \times 10^{- 3}\ ohm^{- 1};\ \mu = 42$, resistance load, $R = 50\ k\Omega$. The voltage amplification obtained from this triode will be

Explanation

Reviewed by Dr. Abubacker

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