Q. For the given combination of gates, if the logic states of inputs $A,\ B,\ C$ are as follows $A = B = C = 0$ and $A = B = 1,\ C = 0$, then the logic states of output $D$ are

A) 0, 0
B) 0, 1
C) 1, 0
D) 1, 1
Explanation

(d) Here Boolean expression is $Y = \overline{(A + B) \bullet C}$. so $Y = \overline{A.B} = \overline{0.1} = 1$ as the boolean expression of it is $Y = \overline{A.B}.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.