Q. A photodetector used to detect the wavelength of 1700 nm, has energy gap of about
A) 0.073 eV
B) 1.2 eV
C) 7.3 eV
D) 0.73 eV
Explanation
(d) Energy = $\frac{hc}{\lambda} = \frac{6.6 \times 10^{- 34} \times {3 \times 10}^{8}}{1700 \times 10^{- 9} \times {1.6 \times 10}^{- 19}}$ eV = 0.73 eV
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.