Q. $14 \times 10^{15}$ electrons reach the anode per second. If the power consumed is $448\ milliwatts$, then the plate (anode) voltage is
A) 150 $V$
B) $200V$
C) $14 \times 448V$
D) $448/14V$
Explanation
(b) $P = Vi \Rightarrow V = \frac{P}{i} = \frac{448 \times 10^{- 3}}{14 \times 10^{15} \times 1.6 \times 10^{- 19}} = 200V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.