Q. In a n-p-n transistor, the collector current is 10mA. If 90% of the electrons emitted reach the collector, then the emitter current will be

A) 9 mA
B) 11 mA
C) 1 mA
D) 0.1 mA
Explanation

(b) In an n-p-n transistor emitter current ($i_{e}$) is the sum of base current ($i_{b}$) and collector current ($i_{c}$).
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Given, $\frac{90}{100}i_{e} = i_{c}$ …(i)
Also, $i_{c} = 10$ mA …(ii)
From Eqs. (i) and (ii), we get
$i_{e} = \frac{10 \times 100}{90} = 11\ mA$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.