Q. The amplification factor of a triode is 18 and its plate resistance is $8 \times 10^{3}\Omega$. A load resistance of $10^{4}\Omega$ is connected in the plate circuit. The voltage gain will be
A) 30
B) 20
C) 10
D) 1
Explanation
(c) Voltage gain $A_{v} = \frac{\mu}{1 + \frac{r_{p}}{R_{L}}} = \frac{18}{1 + \frac{8 \times 10^{3}}{10^{4}}} = 10$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.