Q. In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 $\mu$A. The reverse bias resistance of the diode is
A) $2{\times 10}^{5}\ \Omega$
B) $2{\times 10}^{6}\ \Omega$
C) 200$\ \Omega$
D) 2$\ \Omega$
Explanation
(b) Reverse resistance =$\ \frac{\mathrm{\Delta}V}{\mathrm{\Delta}I} = \frac{1}{{0.5 \times 10}^{- 6}} = 2{\times 10}^{6}\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.