Q. In the circuit shown in figure the maximum output voltage $V_{0}$ is
A) 0 $V$
B) 5 $V$
C) 10 $V$
D) $\frac{5}{\sqrt{2}}V$
Explanation
(b) For the positive half cycle of input the resulting network is shown below
$\Rightarrow \left( V_{0} \right)_{\max} = \frac{1}{2}\left( V_{i} \right)_{\max} = \frac{1}{2} \times 10 = 5\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.