(d) $\lambda = \frac{hc}{E} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{(1.14 \times 1.6 \times 10^{- 19})} = 10,888\mathring{\mathrm{A}}$
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Ph.D. in Physics with 19+ years of teaching experience.