Q. A crystal has bcc structure and its lattice constant is $3.6\ \mathring{\mathrm{A}}$. What is the atomic radius?
A) $3.6\ \mathring{\mathrm{A}}$
B) $1.8\ \mathring{\mathrm{A}}$
C) $1.27\ \mathring{\mathrm{A}}$
D) $1.567\ \mathring{\mathrm{A}}$
Explanation
(d) Atomic radius for bcc structure,
$r = \frac{a\sqrt{3}}{4} = \frac{3.6\sqrt{3}}{4} = 1.56\ \mathring{\mathrm{A}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.