Q. In Boolean algebra, $\overline{\overline{A} \bullet \overline{B}}$ is equal to
A) $\overline{A} \bullet \overline{B}$
B) $\overline{A} + \overline{B}$
C) $A \bullet B$
D) $A + B$
Explanation
(d) According to De-Morgan’s theorem
$\overline{A} \bullet \overline{B} = \left( \overline{A + B} \right)$
$\therefore\overline{\overline{A} \bullet \overline{B}}$) = $\left( \overline{\overline{A + B}} \right)$
= ( A$+ B$) ($\because\overline{\overline{A}} = A)$
$\therefore\overline{\overline{A} \bullet \overline{B}} = \ $(A$\ + B$)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.