Q. The nearest distance between two atoms in case of a bcc lattice is equal to
A) $\frac{a\sqrt{2}}{3}$
B) $\frac{a\sqrt{3}}{2}$
C) $a\sqrt{3}$
D) $\frac{a}{\sqrt{2}}$
Explanation
(b) In a bcc lattice, the atoms touch one another along the body diagonal. For cube of length $a$ and atomic radius $r$, we have
$r$ =$\frac{\sqrt{3}}{4}a$
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$\therefore$ Distance between two atoms = $\frac{2 \times \sqrt{3}a}{4} = \frac{\sqrt{3}}{2}a$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.