Q. The output of an OR gate is connected to both the inputs of a NAND gate. The combination will serve as a
A) OR gate
B) NOT gate
C) NOR gate
D) AND gate
Explanation
(c) ${\ \ \ Y}^{'} = A + B$
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And $Y = {\overline{Y}}^{'} = \overline{A + B}$
ie, out of a NOR gate.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.