Q. A diode is connected to $220\ V\ (rms)ac$ in series with a capacitor as shown in figure. The voltage across the capacitor is
A) 220 $V$
B) 110 $V$
C) 311.1 $V$
D) $\frac{220}{\sqrt{2}}V$
Explanation
(d) The diode $D$ will conduct for positive half cycle of $a.c.$ supply because this is forward biased. For negative half cycle of $a.c.$ supply, this is reverse biased and does not conduct. So out put would be half wave rectified and for half wave rectified out put
$V_{rms} = \frac{V_{0}}{2} = \frac{200\sqrt{2}}{2} = \frac{200}{\sqrt{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.