(d) Here, $h = 150\ km,\ v = 300\ kHz$, $v_{c} = 100\ kHz$ $D_{skip} = 2h\sqrt{\left( \frac{v}{v_{c}} \right)^{2} - 1}$ $= 2 \times 150 \times 10^{3}\sqrt{\left( \frac{300 \times 10^{2}}{100 \times 10^{3}} \right) - 1}$ $= 849\ Hz$
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Ph.D. in Physics with 19+ years of teaching experience.