Q. What should be the maximum acceptance angle at the aircore interface of an optical fibre if $n_{1}$ and $n_{2}$ are the refractive indices of the core and the cladding, respectively
A) $\sin^{- 1}{(n_{2}/n_{1})}$
B) $\sin^{- 1}\sqrt{n_{1}^{2} - n_{2}^{2}}$
C) $\left\lbrack \tan^{- 1}\frac{n_{2}}{n_{1}} \right\rbrack$
D) $\left\lbrack \tan^{- 1}\frac{n_{1}}{n_{2}} \right\rbrack$
Explanation
(b) Core of acceptance angle $\theta = \sin^{- 1}\sqrt{n_{1}^{2} - n_{2}^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.