Q. The normalised fiber frequency is expressed by ($a$=fiber core radius, $\lambda_{0}$=free space wavelength, $\mu_{1},\mu_{2}$= refractive index of core and cladding)
A) $\frac{2\pi a}{\lambda_{0}}\left( \mu_{1}^{2} - \mu_{2}^{2} \right)^{2}$
B) $\frac{2\pi a}{\lambda_{0}}\left( \mu_{1}^{2} - \mu_{2}^{2} \right)^{1/2}$
C) $\frac{2\pi a}{\lambda_{0}}\left( \mu_{1}^{2} - \mu_{2}^{2} \right)^{- 1/2}$
D) $\frac{2\pi a}{\lambda_{0}}(\mu_{1}^{2} - \mu_{2}^{2})$
Explanation
(b) The normalised fiber frequency, $v = \frac{2\pi a}{\lambda_{0}}\left( \mu_{1}^{2} - \mu_{2}^{2} \right)^{1/2}$
$v = \frac{2\pi a}{\lambda_{0}} \times 100 = 1\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.