(b) $C = 1\ nF = 10^{- 9}F,\ L = 10\mu H = 10^{- 5}H$ $v = \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\pi\sqrt{10^{- 5} \times 10^{- 9}}} = \frac{10^{7}}{2\pi}$ $= 1.592 \times 10^{4}\ Hz = 1592\ kHz$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.