(d) $\sqrt{1 + \frac{m^{2}}{2}} = \frac{I_{t}}{I_{c}} = \frac{8.93}{3} = 1.11625$ $\frac{m^{2}}{2} = (1.11625)^{2} - 1$ $m = 0.70 = 70\%$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.