(d) Suppose height of antenna is $h.$ Due to curvature of earth the TV signals will be received on earth in a circle of radius $d.$ Reception range is given by
$d = \sqrt{2hR}$
Here, $h = 500\ m,\ R = 6400\ km$
$\therefore d = \sqrt{2 \times 500 \times 6400 \times 10^{3}}$
$= 80000\ m = 80\ km$