Q. When the modulation percentage is 75, an AM transmitter produces 10 kW. How much of this is carrier power?
A) 10 kW
B) 13.33 kW
C) 7.5 kW
D) 7.81 kW
Explanation
(d) $P_{t} = P_{c}(1 + m^{2}/2)$
$P_{c} = \frac{P_{t}}{1 + m^{2}/2}$
$= \frac{10}{1 + \frac{1}{2}(3/4)^{2}\ } = \frac{10 \times 32}{41}$
$P_{c} = 7.81$ kw
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.