Q. The height of a TV antenna is 200 m. The population density is$4000\ km^{- 2}$. Find the population benefited
A) $3.2 \times 10^{8}$
B) $3.2 \times 10^{7}$
C) $3.2 \times 10^{6}$
D) $3.2 \times 10^{5}$
Explanation
(b) $d = \sqrt{2hR}$;
Population converted$= \pi d^{2} \times$ population density
$= \pi(2Rh) \times \rho$
$= \frac{22}{7} \times 2 \times 6400 \times 0.2 \times 4000$
$= 3.2 \times 10^{7}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.