Q. A TV tower has a height of 150 m. The area of the region covered, the TV broadcast is (radius of earth$= 6.4 \times 10^{6}$m)
A) $9.6\pi{\times 10}^{8}\ km^{2}$
B) $19.2\pi{\times 10}^{8}\ km^{2}$
C) $19.2\pi{\times 10}^{7}\ km^{2}$
D) $1.92\pi{\times 10}^{3}\ km^{2}$
Explanation
(d) Area of region covered $= \pi d^{2} = \pi(2hR)$
$= \pi \times 2 \times 150 \times 6.4 \times 10^{6}$
$= 1.92\ \pi \times 10^{9}\ m^{2} = 1.92\ \pi \times 10^{3}km^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.