Q. An AM wave has $1800\ watt$ of total power content. For 100% modulation the carrier should have power content equal to
A) 1000 $watt$
B) 1200 $watt$
C) 1500 $watt$
D) 1600 $watt$
Explanation
(b) $P_{t} = P_{c}\left( 1 + \frac{m_{a}^{2}}{2} \right);$ Here $m_{a} = 1$
$\Rightarrow 1800 = P_{c}\left( 1 + \frac{(1)^{2}}{2} \right) \Rightarrow P_{c} = 1200W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.