Q. When $\omega_{m}$ is the modulation frequency in frequency modulation, the modulation index is proportional to
A) $\omega_{m}$
B) $\omega_{m}^{2}$
C) ${1/\omega}_{m}$
D) ${1/\omega}_{m}^{2}$
Explanation
(c) In FM, modulation index
$m = \frac{\delta_{\max}}{f_{m}} = \frac{2\pi\delta_{\max}}{2\pi f_{m}} = \frac{2\pi\delta_{\max}}{\omega_{m}}$
$\therefore\ \ \ m \propto \frac{1}{\omega_{m}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.