Q. A gas has a vapour density 11.2. The volume occupied by 1g of the gas at NTP is
A) 1 L
B) 11.2 L
C) 22.4 L
D) 4 L
Explanation
(a)
Given vapour density=11.2
Molecular weight=$2 \times 11.2 = 22.4$
$\therefore$22.4 g of gas occupies=22.4 L at STP
$\therefore$ 1 g of gas occupies=$\frac{22.4}{22.4} \times 1 = 1$ L at STP
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.