Q. For the reaction, ${Na}_{2}{CO}_{3} + 2HCl \rightarrow NaCl + H_{2}O + {CO}_{2}$ Equivalent weight of ${Na}_{2}{CO}_{3}$ is
A) $\frac{M}{2}$
B) M
C) 2M
D) $\frac{M}{4}$
Explanation
(a)
${Na}_{2}{CO}_{3} + 2HCl \rightarrow NaCl + H_{2}O + {CO}_{2}$
In the above reaction equivalent weight of $Na_{2}CO_{3}$ is $\frac{M}{2}$ because 2 moles of $Na^{+}$ being transferred per mole of $Na_{2}CO_{3}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.