Explanation

(a)
$C_{2}H_{4} + 3O_{2} \rightarrow 2CO_{2} + 2H_{2}O$
28 g 96 g
$\because$ The weight of oxygen required for complete combustion of 28 g ethylene=96 g.
$\therefore$ Weight of oxygen required for combustion of 2.8 kg ethylene
$= \frac{96 \times 2.8 \times 1000}{28 \times 1000}\$kg=9.6 kg