Q. The volume of oxygen necessary for the complete combustion of 20 L of propane is
A) 40 L
B) 60 L
C) 80 L
D) 100 L
Explanation
(d)
Combustion of propane takes place as follows
$C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O$
propane oxygen
$\because$ 1 L of propane required 5 L oxygen for combustion.
$\therefore$ 20 L propane required oxygen $= 5 \times 20 = 100$ L
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.