Q. An alkaloid contains $17.28\%$ of nitrogen and it’s molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is
A) 5
B) 4
C) 3
D) 2
Explanation
(d)
100 g alkaloid contains nitrogen=17.28 g
$\therefore$ 162 g alkaloid will contain nitrogen
$= \frac{17.28 \times 162}{100}g$
$= 27.9\ g \approx 28\ g$
Atomic weight of nitrogen=14
So, number of atoms of nitrogen present in one molecular of alkaloid$= \frac{28}{14} = 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.