(c)
Equivalent weight of bivalent metal=37.2
$\therefore$ Atomic weight of metal=$37.2 \times 2 = 74.4$
$\therefore$ Formula of chloride=$MCl_{2}$
Hence, molecular weight of chloride
$MCl_{2} = 74.4 + 2 \times 35.5$
$\ \ \ \ \ \ \ \ \ \ \ = 145.4$