Q. If $w_{1}$ g of a metal $X$ displaces $w_{2}$ g of another metal $Y$ from its salt solution and if the equivalent weights are $E_{1}$ and $E_{2}$ respectively, the correct expression for the equivalent weight of $X$ is
A) $E_{1} = \frac{w_{1}}{w_{2}} \times E_{2}$
B) $E_{1} = \frac{w_{2} \times E_{2}}{w_{1}}$
C) $E_{1} = \frac{w_{1} \times w_{2}}{E_{2}}$
D) $E_{1} = \sqrt{\frac{w_{1}}{w_{2}} \times E_{2}}$
Explanation
(a)
$\frac{wt.of\ metal\ X}{wt.of\ metal\ Y} = \frac{Eq.wt.of\ metal\ X}{Eq.wt.of\ metal\ Y}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.