Q. Arsenic forms two oxides, one of which contains 65.2% and the other 75.5% of the element. Hence, equivalent masses of arsenic are in the ratio
A) 1 : 2
B) 3 : 5
C) 13 : 15
D) 2 : 1
Explanation
(b)
In first oxide,
Mass of arsenic = 65.2
Mass f oxygen = 34.8
$\therefore$ Eq. mass of arsenic $= \frac{65.2}{34.8} \times 8 = 14.99$
In second oxide,
Mass of arsenic = 75.7 g
Mass of oxygen = 24.3 g
$\therefore$ Eq. mass of arsenic $= \frac{75.7}{24.3} \times 8 = 24.92$
Eq. mass of arsenic : Eq. mass of arsenic
(oxide I) (oxide II)
14.99 : 24.92
Or 3 : 5
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.