Q. What is the number of moles of Fe$(OH)_{3}(s)$ that can be produced by allowing 1 mole of $Fe_{2}S_{3}$, 2 moles of $H_{2}O$ and 3 moles of $O_{2}$ to react as $2Fe_{2}S_{3} + 6H_{2}O + 3O_{2} \longrightarrow 4Fe(OH)_{3} + 6S?$
A) 1 mol
B) 1.84 mol
C) 1.34 mol
D) 1.29 mol
Explanation
(c)
$H_{2}O$ is the limiting reagent for the above equation.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.