Q. NO reacts with$O_{2}$ to form $No_{2}.$ When 10 g of $NO_{2}$ is formed during the reaction, the mass of $O_{2}$ consumed is
A) 1.90 g
B) 5.0 g
C) 3.48 g
D) 13.9 g
Explanation
(c)
$2NO + O_{2} \longrightarrow 2NO_{2}$
32g $2 \times 46$g
$\because$ 92 g $NO_{2}$ uses $O_{2} = 32$g
$\therefore 10$ g $NO_{2}\$uses $O_{2} = \frac{32}{92} \times 10 = 3.48$g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.