(c) $2\left( NH_{4} \right)_{2}HPO_{4} \equiv P_{2}O_{5}$ 264g 142g % of $P_{2}O_{2} = \frac{wt.of\ P_{2}O_{5}}{wt.of\ salt}\mathbf{\times}100$ $= \frac{142}{264} \times 100$ $= 53.78\%$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.