If in a reaction $HNO_{3}$ is reduced to $NO,$ the mass of $HNO_{3}$ absorbing one mole of electrons would be

Question

Dr. Abubacker · Accepted Answer

(a)
We have $H{NO}_{3}^{+ 5} ightarrow \ \begin{matrix}
 + 2 \
NO
\end{matrix}$
Change in oxidation number = 3
Equivalent mass of $HNO_{3} = \frac{63g\ mol^{- 1}}{3\ eq\ mol^{- 1}} = 21\ g\ eq^{- 1}$

Q. If in a reaction $HNO_{3}$ is reduced to $NO,$ the mass of $HNO_{3}$ absorbing one mole of electrons would be

Explanation

Reviewed by Dr. Abubacker

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