Q. What amount of bromine will be required to convert 2 g of phenol into 2, 4, 6-tribromo phenol?
A) 20.44 g
B) 6.00 g
C) 4.00 g
D) 10.22 g
Explanation
(d)
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Molecular weight of $C_{6}H_{5}OH = 94$
Atomic weight of Br=80
Amount of Br utilized=480 g
$\because$ 94 g of $C_{6}H_{5}OH$ reacts with 480 g of bromine.
$\therefore$ 2g of $C_{6}H_{5}OH$ will react with=$\frac{480 \times 2}{94}$
=10.2 g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.